SIMPLE MACHINES / WEDGE
Why does a shallow wedge need less pushing force?
Use horizontal travel to lift a vertical load by a smaller distance.
ORIGINAL IDEAL EXAMPLE
500 N load
100 N effort
For the ideal single wedge, horizontal input work equals vertical output work. A shallow working face trades travel for force.
Conceptual schematic; use the model below for parameter-linked geometry.Wedge working face selected · related inputs are marked.
BASELINE INPUTS
CALCULATED
Edits change the baseline source.
Calculated from the same .napkin source. Edits preview a temporary study and are not saved.
How the model works
For the ideal single wedge, horizontal input work equals vertical output work. A shallow working face trades travel for force.
effort = load × rise / lengthTry the alternative
A steeper wedge increases lift per push but requires more force. This example is a lifting wedge, not a cutting or fracture model.
Choose a scenario, change an input, then inspect the equations and force check in Source.
Assumptions and limits
Friction, self-locking, contact stresses and material fracture are omitted. The geometric model shows the inclined working face rather than a solid wedge feature.