SIMPLE MACHINES / SCREW

How does a screw turn a small hand force into a large axial force?

Compare screw lead, handle radius, required torque and hand force.

EffortLoad

ORIGINAL IDEAL EXAMPLE

500 N load
3.97887 N effort

One turn moves the hand through a circle while the load advances by the screw lead. In the ideal model, those two motions exchange equal work.

Conceptual schematic; use the model below for parameter-linked geometry.
screw.napkin / editable
✓ checks pass
Screw shaftHandle
XZ / UNDEFORMED GEOMETRYFITTED TO VIEW

Screw shaft selected · related inputs are marked.

hand force3.98 N✓ passes

BASELINE INPUTS

CALCULATED

torque0.39789 N*m
effort3.9789 N
mechanicalAdvantage125.66
handleLength200 mm

Edits change the baseline source.

Calculated from your source · not saved
Baseline · Baseline
hand force3.98 N ✓ passes
coarser lead · coarser lead
hand force7.96 N × fails

Calculated from the same .napkin source. Edits preview a temporary study and are not saved.

How the model works

One turn moves the hand through a circle while the load advances by the screw lead. In the ideal model, those two motions exchange equal work.

torque = load × lead / (2π); effort = torque / handleRadius

Try the alternative

A finer lead reduces torque and hand force but requires more turns. Lead is advance per revolution; it equals pitch only for a single-start thread.

Choose a scenario, change an input, then inspect the equations and force check in Source.

Assumptions and limits

Thread and collar friction, efficiency, self-locking, buckling and thread strength are omitted. The drawing is a schematic shaft and handle without modeled threads.